MAH MBA CET Odd Man Out Questions

In each of the options, the third letter is the letter n placed away from the first letter where ‘n’ is the number which is given between the two letters.

A) C7J = C+7 = J

B) M4Q = M+4 = Q

C) P3S = P+3 = S

D) F7M = F+7 = M

E) J8S = J+8 = R

Thus, option E is the odd one out.

Let's analyze the pattern

9B18 - $$9\times2\left(B\right)=18$$

7E35 - $$7\times5\left(E\right)=35$$

6G48 - $$6\times7\left(G\right)\ne48$$

5R90 - $$5\times18\left(R\right)=90$$

4P64 - $$4\times16\left(P\right)=64$$

8J80 - $$8\times10\left(J\right)=80$$

Hence, 6G48 is the Odd one out.

Every option other than Option D have their digits adding up to 17. 

All the numbers except 36 are thrice of a prime number.
i.e. 11*3, 2*3, 17*3, 29*3

However, 36 is a composite number multiplied with 3.

CFLX = 3 6 12 24

ABDH = 1 2 4 8

EJTN = 5 10 20 40(40%26 = 14) 

BDHP = 2 4 8 16

GNBE = 7 14 28(%26 = 2) 56(%26 = 4)

7 14 2 4 = GNBD

So, this is incorrect.

C is the 3rd letter

E is the 5th letter

I is the 9th letter

O is the 15th letter

3, 3+2, 5+4, 9+6, 15+8 = 23

So, we are looking for the 23rd letter which is W. 

The numbers are just prime numbers in order, so the next prime number is 11. 

Let's analyze the pattern:

• 2 = 1 × 2
• 6 = 2 × 3
• 12 = 3 × 4
• 20 = 4 × 5
• 30 = 5 × 6
• 42 = 6 × 7
• 56 = 7 × 8
• 74 ≠ 8 × 9
• 90 = 9 × 10

The pattern here is that each number is the product of two consecutive integers.

However, 74 does not follow the same pattern.

Hence, 74 is the odd one out.

The position of the letters in the alphabet corresponds to whether the numbers that follow are even or odd.
For letters in odd positions (A = 1, C = 3, E = 5, G = 7, I = 9), they are paired with odd numbers.
For letters in even positions (B = 2, D = 4, F = 6, H = 8, J = 10), they are paired with even numbers.

Option E: I (odd, 9) paired with 4 (even), J (even, 10) paired with 7 (odd) — Violates the pattern because the first letter (odd) is not paired with an odd number, the same goes for the second letter as well. 

Let's check option A first to understand the series.
N is the 14th letter, Z is the 26th letter, A is the 1st letter and M is the 13th letter in the aphabetical series.
So, the position of the first letter 'N' from the beginning of the alphabetical series is equal to the position of the last letter 'M' from the end of the alphabetical series. Both are 14.
Similarly, the position of the second letter 'Z' from the first in the alphabetical series is equal to the position of the second last letter from the end of the alphabetical series. Both are 1.
Let's check if this holds true for the second option.
The position of the letter F is 6 and I is 9. The position of the letters R and U from the end of the alphabetical series is 9 and 6 respectively.
Hence, this logic holds true. The option that doesn't follow this logic is wrong.
In option D, E is 5th letter and V is 22nd letter. C and X are 24th and 3rd letters respectively from the end of the alphabetical series. Hence it is wrong.

In each of the options the third letter is the letter is n places away from the first letter where ‘n’ is the number which is given between the two letters. For example, G is third letter after D, T is seventh letter after M and so on. This rule is not followed in option D. As per the rule, it should be N5S. Thus, option D is the odd one out.

All the numbers except 225 are squares of prime numbers. Hence 225 is the odd one out. Thus option D is the correct answer.

The series is third_letter --> fourth_letter --> second_letter --> first_letter.
The third letter, fourth letter and the second letter are in a series while there is a gap of one letter between the first letter and the second letter.
This logic is not followed by option C as there is no gap of 1 letter between O and P.
Hence, C is the answer.

All other options other than option D have their digits adding up to 15.