MAH MBA CET Directions Questions

1. Starting Direction: Ravi begins facing North.
2. First Movement: He walks 8 meters straight (still facing North).
3. First Turn: He takes a left turn, so now he faces West. He walks 6 meters.
4. Second Turn: He takes another left turn, so now he faces South. He walks 10 meters.
5. Third Turn: He takes a right turn, so now he faces West. He walks 4 meters.
6. Fourth Turn: He takes another right turn, so now he faces North. He walks 6 meters.
7. Final Turn: He takes a left turn, so now he faces West. He walks 2 meters.
After the entire journey, Ravi is facing West.

The final point is 40 m south and 9m west to the starting point.

So, the distance between the two points is $$\sqrt{9^2+40^2}=41m$$

Hence the answer is 41m, south-west.

Let's assume that he moves s meters every 30 minutes. 

So he first travels 2s meters to the north, then turns left, facing west and walks s meters in that direction, after which he turns 90 degrees clockwise, now facing north again and walks s meter again. 

Then turns 90 degree clockwise yet again, facing east and walks 2s meters, and then turns towards south and walks 2s meters in that direction. 

So, he is essentially s meters north and s meters east of his original position. 

So he is $$s\sqrt{\ 2}$$ m away from the starting point. 

This would take him approximately $$30\times\ \sqrt{\ 2}\approx\ 30\times\ 1.41\approx\ 42$$ minutes. 

Therefore, Option B is the correct answer. 

The given situation can be represented through the following figure. Let S, C be the starting and current points of Neeraj.

Hence the distance from S to C can be obtained by using Pythagoras theorem.
SC = $$\sqrt{8^{2} + 1^{2}} = \sqrt{65}$$

In the North Direction Rahul has travelled (12 + 10 - 1)m = 21m.
In the East Direction Rahul has travelled (15+6-1) m = 20m.
By Pythagoras Theorem, total distance travelled => d
=> d = $$\sqrt{20^2+21^2}$$ = 29 m

If Rahul stops at E, he travels (12+10-1) = 21m in the North Direction
and he has travelled (15 + 6) = 21m in the East Direction.
Therefore, Rahul is currently in the North-East direction with respect to the initial position.
So, he should look in opposite , i.e. , South-West direction to see his initial position.

Rushi's actions can be traced into the following diagram, 

To find the distance between the starting and the final point we can basically sketch out the right-angle triangle involved. 
We know that the ending point is 40 feet away horizontally and 30 feet away vertically. 

Hence the distance between the starting and the camping point is 50 feet. 

Rushi's actions can be traced into the following diagram,

From the camped spot to the point where he discovered magic mushrooms it is a right-angled triangle with sides 40 and 20. 
Distance would be: $$\sqrt{1600+400}=20\sqrt{5}$$
Which approximately is: 44.72, nearest integer is 45. 

From B to E, we can see that Ram would be travelling in a straight line parallel to the line CD and the distance would be same as the length of CD. Therefore, the shortest distance between B and E would be 3 km. Hence, option C is correct

From Home to E, Ram has traveled 5 km in south direction
and Ram has traveled ( 3 + 3 ) km = 6 km in West direction.
The shortest distance would be => $$ \sqrt{ 6^2 + 5^2 } $$ km = $$ \sqrt{61} $$ km
Hence, option D is correct