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Given below is the diagram which represents various sports played by the students. Based on the diagram find the number of girls who neither play hockey nor football
From the given diagram, we can see that '6' is neither included in the triangle nor the rectangle, implying 6 girls don't participate in hockey or football.
Therefore, the correct option is A.
Given below are two statements :
Statement I: If 'some students are intelligent' is true, then 'some students are not intelligent' is also true.
Statement II: If 'all logicians are mathematician' is true, then 'some non-mathematicians are not logicians' will be true.
In the light of the above statements, choose the correct answer from the options given below.
Statement I is false because some students are intelligent implies two cases: 1. all the students are intelligent. 2. some students are not intelligent.
Any of these can be correct. Hence, statement 1 is also false.
Statement II is true since all the logicians are mathematicians, which implies that all the non-mathematicians can't be logicians, which implies some non-mathematicians are not logicians.
The correct option is D.
If 'All sweet things are fluids' and 'Some fluids are coloured things', then it implies -
A. Some sweet things are coloured things
B. Some sweet things are fluids
C. All fluids are sweet things
D. Some fluids are sweet things
Choose the most appropriate answer from the options given below:
This is a previous year question, which is wrong in the question paper itself. But the correct answer is B,D.
Out of 400 students who attended a seminar, 240 opted for written exam, 200 opted for presentations, 160 opted for assignments and 20 did not opt for giving any of the three methods of test. 200 students had exactly one of the three methods of test.
How many students opted for exactly two of the three testing methods?
20 did not appear for any of the three methods. Hence, the total number of students who appeared in the tests (400-20) = 380.
(240+160+200)=600 students
=> Exactly I + 2 (Exactly II) + 3(Exactly III) => 2(Exactly II) + 3 (Exactly III) = 400
Exactly I +Exactly II + Exactly III = 380
Exactly II + Exactly III = 180 .......equation (i)
=> 2(Exactly II) + 2(Exactly III) = 360 .......equation (ii)
Subtracting equations (ii) by (i)
=> Exactly III = 40
Therefore, Exactly II = 180-40 = 140.
Hence, the correct option is A.
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